What is the tangent of 2x^2+3x-2 ?

The tangent of 2x^2+3x-2 is y=(4a_{0}+3)x-2a_{0}^2-2

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tangent of 2x^2+3x-2

tangent of

2 x^{2} + 3 x - 2

y = (4 a_{0} + 3) x - 2 a_{0}^{2} - 2

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 2 a_{0}^{2} + 3 a_{0} - 2)

Find the slope of

y = 2 x^{2} + 3 x - 2 : \frac{d y}{d x} = 4 x + 3

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 4 a_{0} + 3

Find the line with slope m=

4 a_{0} + 3

and passing through

(a_{0}, 2 a_{0}^{2} + 3 a_{0} - 2) : y = (4 a_{0} + 3) x - 2 a_{0}^{2} - 2

y = (4 a_{0} + 3) x - 2 a_{0}^{2} - 2

f (t) = \frac{6 t + 38}{t + 9}

\int_{1}^{6} \frac{x ^{2} + 1}{7 x - x ^{2}} d x

\frac{d}{d x} (π x)

\frac{d y}{d x} + \frac{4}{x} y = - 3 x

\frac{1}{( s ^{2} + 2 s + 1 )}

What is the tangent of 2x^2+3x-2 ?
The tangent of 2x^2+3x-2 is y=(4a_{0}+3)x-2a_{0}^2-2