What is the solution for (dy)/(dx)+4/x y=-3x ?

The solution for (dy)/(dx)+4/x y=-3x is y=-(x^2)/2+(c_{1})/(x^4)

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(dy)/(dx)+4/x y=-3x

\frac{d y}{d x} + \frac{4}{x} y = - 3 x

y = - \frac{x ^{2}}{2} + \frac{c _{1}}{x ^{4}}

Solution steps

\frac{d y}{d x} + \frac{4}{x} y = - 3 x

Solve linear ODE:

y = - \frac{x ^{2}}{2} + \frac{c _{1}}{x ^{4}}

y = - \frac{x ^{2}}{2} + \frac{c _{1}}{x ^{4}}

\frac{1}{( s ^{2} + 2 s + 1 )}

\frac{d}{d x} (\frac{e ^{x}}{( 1 - e ^{x} ) ^{2}})

f (t) = - 2

x \to 0 lim (\frac{0}{x ^{6}})

y = x^{2} + 2 x

What is the solution for (dy)/(dx)+4/x y=-3x ?
The solution for (dy)/(dx)+4/x y=-3x is y=-(x^2)/2+(c_{1})/(x^4)