What is the derivative of y=x^2+2x ?

The derivative of y=x^2+2x is 2x+2

What is the first derivative of y=x^2+2x ?

The first derivative of y=x^2+2x is 2x+2

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derivative of

y = x^{2} + 2 x

2 x + 2

Solution steps

\frac{d}{d x} (x^{2} + 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (2 x)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (2 x) = 2

= 2 x + 2

x \to 0 lim (x ln (x^{2}))

x \to \infty lim (e^{a x})

\frac{d}{d x} (ln (x^{2} + 7))

(x^{- 1})^{^{'}}

(x - 1)^{2} (x - 1.05)^{2}

What is the derivative of y=x^2+2x ?
The derivative of y=x^2+2x is 2x+2
What is the first derivative of y=x^2+2x ?
The first derivative of y=x^2+2x is 2x+2