What is the derivative of sqrt(1+4x^2) ?

The derivative of sqrt(1+4x^2) is (4x)/(sqrt(1+4x^2))

What is the first derivative of sqrt(1+4x^2) ?

The first derivative of sqrt(1+4x^2) is (4x)/(sqrt(1+4x^2))

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derivative of

1 + 4 x^{2}

\frac{4 x}{1 + 4 x ^{2}}

Solution steps

\frac{d}{d x} (1 + 4 x^{2})

Apply the chain rule:

\frac{1}{2 1 + 4 x ^{2}} \frac{d}{d x} (1 + 4 x^{2})

= \frac{1}{2 1 + 4 x ^{2}} \frac{d}{d x} (1 + 4 x^{2})

\frac{d}{d x} (1 + 4 x^{2}) = 8 x

= \frac{1}{2 1 + 4 x ^{2}} \cdot 8 x

Simplify

\frac{1}{2 1 + 4 x ^{2}} \cdot 8 x : \frac{4 x}{1 + 4 x ^{2}}

= \frac{4 x}{1 + 4 x ^{2}}

5 (t - 4)

\int \frac{x ^{2} + 2 + x}{3 2 + x} d x

x^{2} \cdot 2

x \to \infty lim (- 2 e^{- x} + 2)

\int 3 x y d y

What is the derivative of sqrt(1+4x^2) ?
The derivative of sqrt(1+4x^2) is (4x)/(sqrt(1+4x^2))
What is the first derivative of sqrt(1+4x^2) ?
The first derivative of sqrt(1+4x^2) is (4x)/(sqrt(1+4x^2))