What is the integral of (e^{-2x})/(x^2) ?

The integral of (e^{-2x})/(x^2) is -(e^{-2x})/x-2\Ei(-2x)+C

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integral of (e^{-2x})/(x^2)

\int \frac{e ^{- 2 x}}{x ^{2}} d x

- \frac{e ^{- 2 x}}{x} - 2 Ei (- 2 x) + C

Solution steps

\int \frac{e ^{- 2 x}}{x ^{2}} d x

Apply Integration By Parts

: - \frac{e ^{- 2 x}}{x} - \int \frac{2 e ^{- 2 x}}{x} d x

= - \frac{e ^{- 2 x}}{x} - \int \frac{2 e ^{- 2 x}}{x} d x

\int \frac{2 e ^{- 2 x}}{x} d x = 2 Ei (- 2 x)

= - \frac{e ^{- 2 x}}{x} - 2 Ei (- 2 x)

Add a constant to the solution

= - \frac{e ^{- 2 x}}{x} - 2 Ei (- 2 x) + C

\int_{0}^{\frac{π}{3}} sec^{4} (x) d x

f (x) = 8 - x^{2}

\int u^{1} d u

y^{(\frac{1}{2})} \frac{d y}{d x} + y^{(\frac{3}{2})} = 1, y (0) = 9

f (x) = cos (x) - 1

What is the integral of (e^{-2x})/(x^2) ?
The integral of (e^{-2x})/(x^2) is -(e^{-2x})/x-2\Ei(-2x)+C