What is laplacetransform 3e^{-t} ?

The answer to laplacetransform 3e^{-t} is 3/(s+1)

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laplacetransform 3e^{-t}

laplace transform

3 e^{- t}

\frac{3}{s + 1}

Solution steps

L {3 e^{- t}}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 3 L {e^{- t}}

L {e^{- t}} : \frac{1}{s + 1}

= 3 \cdot \frac{1}{s + 1}

Refine

3 \frac{1}{s + 1} : \frac{3}{s + 1}

= \frac{3}{s + 1}

s \to \frac{2}{3} lim (3 s (2 s - 1))

\int \frac{9}{64 + 4 r ^{2}} d r

\frac{d}{d x} (9 x^{3} - 7 x)

\frac{d}{d x} ((x^{3} + 3)^{5})

\int \frac{1}{( x + 4 ) x ^{2} + 8 x + 12} d x

What is laplacetransform 3e^{-t} ?
The answer to laplacetransform 3e^{-t} is 3/(s+1)