What is (\partial)/(\partial x)(5x^4+y^8) ?

The answer to (\partial)/(\partial x)(5x^4+y^8) is 20x^3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(5x^4+y^8)

\frac{\partial}{\partial x} (5 x^{4} + y^{8})

20 x^{3}

Solution steps

\frac{\partial}{\partial x} (5 x^{4} + y^{8})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (5 x^{4}) + \frac{\partial}{\partial x} (y^{8})

\frac{\partial}{\partial x} (5 x^{4}) = 20 x^{3}

\frac{\partial}{\partial x} (y^{8}) = 0

= 20 x^{3} + 0

Simplify

= 20 x^{3}

\frac{d}{d x} ((\frac{3 x + 512}{x + 1})^{\frac{2}{3}})

y y^{^{'}} = \frac{x}{x ^{2} + 1}, y (0) = - 2

\frac{d y}{d x} - \frac{y}{3 x} + \frac{x}{3 y} = 0

\int x sin^{2} (6 x) d x

\frac{d}{d x} (4 x^{3} - 46 x^{2} + 120 x)

What is (\partial)/(\partial x)(5x^4+y^8) ?
The answer to (\partial)/(\partial x)(5x^4+y^8) is 20x^3