What is the solution for (dy)/(dx)= 1/x (y^2+0.6y) ?

The solution for (dy)/(dx)= 1/x (y^2+0.6y) is y=(0.6e^{0.6c_{1}}x^{0.6})/(1-e^{0.6c_{1)}x^{0.6}}

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(dy)/(dx)= 1/x (y^2+0.6y)

\frac{d y}{d x} = \frac{1}{x} (y^{2} + 0.6 y)

y = \frac{0.6 e ^{0.6 c_{1}} x ^{0.6}}{1 - e ^{0.6 c_{1}} x ^{0.6}}

Solution steps

\frac{d y}{d x} = \frac{1}{x} (y^{2} + 0.6 y)

Solve separable ODE:

y = \frac{0.6 e ^{0.6 c_{1}} x ^{0.6}}{1 - e ^{0.6 c_{1}} x ^{0.6}}

y = \frac{0.6 e ^{0.6 c_{1}} x ^{0.6}}{1 - e ^{0.6 c_{1}} x ^{0.6}}

\int_{- 1}^{3} - x^{2} + 2 x + 3 d x

f^{^{'}} (x) = x (3 + 5 x), f (1) = 7

\int \frac{sin ( x )}{sin ( x ) + cos ( x )} d x

f, tan (f) (x) = 7 x^{4} + 4 \frac{x}{2} x^{3} + 1

\int (\frac{1}{x ^{3}} + \frac{7}{x ^{2}}) d x

What is the solution for (dy)/(dx)= 1/x (y^2+0.6y) ?
The solution for (dy)/(dx)= 1/x (y^2+0.6y) is y=(0.6e^{0.6c_{1}}x^{0.6})/(1-e^{0.6c_{1)}x^{0.6}}