What is the tangent of f(x)= 8/x ,\at x=4 ?

The tangent of f(x)= 8/x ,\at x=4 is y=-1/2 x+4

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tangent of f(x)= 8/x ,\at x=4

tangent of

f (x) = \frac{8}{x}, at x = 4

y = - \frac{1}{2} x + 4

Solution steps

Find the tangent point:

(4, 2)

Find the slope of

f (x) = \frac{8}{x} : \frac{df ( x )}{d x} = - \frac{8}{x ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{1}{2}

Find the line with slope m=

- \frac{1}{2}

and passing through

(4, 2) : y = - \frac{1}{2} x + 4

y = - \frac{1}{2} x + 4

y = 2 x, 2 x - 4, y = 0

5 x^{3} - 10 x^{2} - \frac{3}{x}

\frac{d}{d x} (sin (x^{3} + 2 x - 1))

\frac{d y}{d t} = 5 y + y^{4}, y (0) = 1

1 - cos^{2} (17 x)

What is the tangent of f(x)= 8/x ,\at x=4 ?
The tangent of f(x)= 8/x ,\at x=4 is y=-1/2 x+4