What is the sum from n=4 to infinity of (7^n)/(14^n) ?

The sum from n=4 to infinity of (7^n)/(14^n) is converges

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sum from n=4 to infinity of (7^n)/(14^n)

n = 4 \sum \infty \frac{7 ^{n}}{1 4 ^{n}}

converges

Solution steps

n = 4 \sum \infty \frac{7 ^{n}}{1 4 ^{n}}

n \to \infty lim (n (\frac{\frac{7 ^{n}}{1 4 ^{n}}}{\frac{7 ^{n + 1}}{1 4 ^{n + 1}}} - 1)) = \infty

L > 1,

by the Raabe's test

= converges

\frac{d y}{d x}, x = sec (4 y)

\frac{d}{d x} ((x^{2} + 3) (x^{2} - 2)^{8})

4 sin (x) sin (y) + cos (y) y^{^{'}} = 0

f (x) = 4 x^{2} + 12 x + 5, at (- 1)

\int x^{5} x^{3} + 2 d x

What is the sum from n=4 to infinity of (7^n)/(14^n) ?
The sum from n=4 to infinity of (7^n)/(14^n) is converges