What is the sum from n=1 to infinity of \sqrt[n]{2} ?

The sum from n=1 to infinity of \sqrt[n]{2} is diverges

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sum from n=1 to infinity of \sqrt[n]{2}

n = 1 \sum \infty n 2

diverges

Solution steps

n = 1 \sum \infty n 2

Apply Series Divergence Test:

diverges

= diverges

y^{^{'}} - 2 = 2 y^{2}

(4, 0), (0, - 1)

\frac{d}{d x} (\frac{5 + 6 x}{9 - 4 x})

f (1) = x + \frac{1}{x}

\frac{d}{d x} (\frac{x}{( x ^{2} + 1 ) ^{2}})

What is the sum from n=1 to infinity of \sqrt[n]{2} ?
The sum from n=1 to infinity of \sqrt[n]{2} is diverges