What is the derivative of f(1)=x+1/x ?

The derivative of f(1)=x+1/x is 1-1/(x^2)

What is the first derivative of f(1)=x+1/x ?

The first derivative of f(1)=x+1/x is 1-1/(x^2)

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derivative of

f (1) = x + \frac{1}{x}

1 - \frac{1}{x ^{2}}

Solution steps

\frac{d}{d x} (x + \frac{1}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (\frac{1}{x})

\frac{d x}{d x} = 1

\frac{d}{d x} (\frac{1}{x}) = - \frac{1}{x ^{2}}

= 1 - \frac{1}{x ^{2}}

\frac{d}{d x} (\frac{x}{( x ^{2} + 1 ) ^{2}})

\int \frac{12}{1 + 4 x ^{2}} d x

\frac{d}{d x} (3 x^{9.6} + 2 e^{1.3})

\int_{1}^{2} (\frac{1}{t} - i)^{2} d t

y^{^{'}} = a y - b y^{2}

What is the derivative of f(1)=x+1/x ?
The derivative of f(1)=x+1/x is 1-1/(x^2)
What is the first derivative of f(1)=x+1/x ?
The first derivative of f(1)=x+1/x is 1-1/(x^2)