What is the derivative of \sqrt[3]{x^{9.6}}+2e^{1.3} ?

The derivative of \sqrt[3]{x^{9.6}}+2e^{1.3} is 3.2x^{2.2}

What is the first derivative of \sqrt[3]{x^{9.6}}+2e^{1.3} ?

The first derivative of \sqrt[3]{x^{9.6}}+2e^{1.3} is 3.2x^{2.2}

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\frac{d}{d x} (3 x^{9.6} + 2 e^{1.3})

3.2 x^{2.2}

Solution steps

\frac{d}{d x} (3 x^{9.6} + 2 e^{1.3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{9.6}) + \frac{d}{d x} (2 e^{1.3})

\frac{d}{d x} (3 x^{9.6}) = 3.2 x^{2.2}

\frac{d}{d x} (2 e^{1.3}) = 0

= 3.2 x^{2.2} + 0

Simplify

= 3.2 x^{2.2}

\int_{1}^{2} (\frac{1}{t} - i)^{2} d t

y^{^{'}} = a y - b y^{2}

\frac{d}{d x} (\frac{x ^{8}}{16})

\frac{d}{d t} (\frac{1}{t})

x \to 1 + lim (\frac{x + 2}{x + 1})

What is the derivative of \sqrt[3]{x^{9.6}}+2e^{1.3} ?
The derivative of \sqrt[3]{x^{9.6}}+2e^{1.3} is 3.2x^{2.2}
What is the first derivative of \sqrt[3]{x^{9.6}}+2e^{1.3} ?
The first derivative of \sqrt[3]{x^{9.6}}+2e^{1.3} is 3.2x^{2.2}