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Popular >

xy^'+y=0,y(4)=6

Solution

x y^{^{'}} + y = 0, y (4) = 6

Solution

y = \frac{24}{x}

Solution steps

x y^{'} (x) + y = 0

Solve separable ODE:

y = \frac{24}{x}

y = \frac{24}{x}

Graph

Popular Examples

derivative of f(x)= 4/x-2/(x^3)+1/(x^4)derivative of

f (x) = \frac{4}{x} - \frac{2}{x ^{3}} + \frac{1}{x ^{4}}

tangent of y=-7/2 x^2+5x+5,(-1,-7/2)tangent of

y = - \frac{7}{2} x^{2} + 5 x + 5, (- 1, - \frac{7}{2})

integral of cos^3(x)sin^{-4}(x)

\int cos^{3} (x) sin^{- 4} (x) d x

(dy)/(dx)=((x^3))/(y^2)

\frac{d y}{d x} = \frac{( x ^{3} )}{y ^{2}}

integral of (4e^x-x^3+6x-8)

\int (4 e^{x} - x^{3} + 6 x - 8) d x

Frequently Asked Questions (FAQ)

What is the solution for xy^'+y=0,y(4)=6 ?
The solution for xy^'+y=0,y(4)=6 is y=(24)/x