What is (\partial ^2)/(\partial x^2)(2cos(xy^2)) ?

The answer to (\partial ^2)/(\partial x^2)(2cos(xy^2)) is -2y^4cos(xy^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial ^2)/(\partial x^2)(2cos(xy^2))

\frac{\partial ^{2}}{\partial x ^{2}} (2 cos (x y^{2}))

- 2 y^{4} cos (x y^{2})

Solution steps

\frac{\partial ^{2}}{\partial x ^{2}} (2 cos (x y^{2}))

\frac{\partial}{\partial x} (2 cos (x y^{2})) = - 2 y^{2} sin (x y^{2})

= \frac{\partial}{\partial x} (- 2 y^{2} sin (x y^{2}))

\frac{\partial}{\partial x} (- 2 y^{2} sin (x y^{2})) = - 2 y^{4} cos (x y^{2})

= - 2 y^{4} cos (x y^{2})

(\frac{d y}{d x}) = (x + y + 7)^{2}

- \frac{x 1 - y ^{2}}{y 1 - x ^{2}} = \frac{d y}{d x}

n = 0 \sum \infty \frac{n ^{2} + 1}{n !}

\int sin (3 x) cos (3 x) d x

\frac{d}{d u} (\frac{u - 1}{u + 1})

What is (\partial ^2)/(\partial x^2)(2cos(xy^2)) ?
The answer to (\partial ^2)/(\partial x^2)(2cos(xy^2)) is -2y^4cos(xy^2)