What is the derivative of y= 5/(4x+1) ?

The derivative of y= 5/(4x+1) is -(20)/((4x+1)^2)

What is the first derivative of y= 5/(4x+1) ?

The first derivative of y= 5/(4x+1) is -(20)/((4x+1)^2)

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derivative of

y = \frac{5}{4 x + 1}

- \frac{20}{( 4 x + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{5}{4 x + 1})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d x} (\frac{1}{4 x + 1})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 5 \frac{d}{d x} ((4 x + 1)^{- 1})

Apply the chain rule:

- \frac{1}{( 4 x + 1 ) ^{2}} \frac{d}{d x} (4 x + 1)

= - \frac{1}{( 4 x + 1 ) ^{2}} \frac{d}{d x} (4 x + 1)

\frac{d}{d x} (4 x + 1) = 4

= 5 (- \frac{1}{( 4 x + 1 ) ^{2}} \cdot 4)

Simplify

5 (- \frac{1}{( 4 x + 1 ) ^{2}} \cdot 4) : - \frac{20}{( 4 x + 1 ) ^{2}}

= - \frac{20}{( 4 x + 1 ) ^{2}}

y = x^{3 \cdot 7}

f (x) = \frac{( x ^{2} - 3 x )}{2}

\frac{\partial}{\partial x} (x^{2} + y^{2} + x y + 3)

\frac{d y}{d x} = \frac{x ^{2} - 9}{x}

\int_{0}^{3} x e^{- 4 x} d x

What is the derivative of y= 5/(4x+1) ?
The derivative of y= 5/(4x+1) is -(20)/((4x+1)^2)
What is the first derivative of y= 5/(4x+1) ?
The first derivative of y= 5/(4x+1) is -(20)/((4x+1)^2)