What is (\partial)/(\partial x)(x^2+y^2+xy+3) ?

The answer to (\partial)/(\partial x)(x^2+y^2+xy+3) is 2x+y

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(\partial)/(\partial x)(x^2+y^2+xy+3)

\frac{\partial}{\partial x} (x^{2} + y^{2} + x y + 3)

2 x + y

Solution steps

\frac{\partial}{\partial x} (x^{2} + y^{2} + x y + 3)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) + \frac{\partial}{\partial x} (y^{2}) + \frac{\partial}{\partial x} (x y) + \frac{\partial}{\partial x} (3)

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (y^{2}) = 0

\frac{\partial}{\partial x} (x y) = y

\frac{\partial}{\partial x} (3) = 0

= 2 x + 0 + y + 0

Simplify

= 2 x + y

\frac{d y}{d x} = \frac{x ^{2} - 9}{x}

\int_{0}^{3} x e^{- 4 x} d x

y = 5 e^{x} + 7 ln (x)

\frac{\partial}{\partial x} (1 + x^{3} + x^{4})

\frac{d}{d x} (\frac{7}{x ^{2} - x + 2})

What is (\partial)/(\partial x)(x^2+y^2+xy+3) ?
The answer to (\partial)/(\partial x)(x^2+y^2+xy+3) is 2x+y