What is (\partial)/(\partial x)(1+x^3+x^4) ?

The answer to (\partial)/(\partial x)(1+x^3+x^4) is 4x^3+3x^2

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(\partial)/(\partial x)(1+x^3+x^4)

\frac{\partial}{\partial x} (1 + x^{3} + x^{4})

4 x^{3} + 3 x^{2}

Solution steps

\frac{\partial}{\partial x} (1 + x^{3} + x^{4})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (1) + \frac{\partial}{\partial x} (x^{3}) + \frac{\partial}{\partial x} (x^{4})

\frac{\partial}{\partial x} (1) = 0

\frac{\partial}{\partial x} (x^{3}) = 3 x^{2}

\frac{\partial}{\partial x} (x^{4}) = 4 x^{3}

= 0 + 3 x^{2} + 4 x^{3}

Simplify

= 4 x^{3} + 3 x^{2}

\frac{d}{d x} (\frac{7}{x ^{2} - x + 2})

y^{^{''}} - y^{^{'}} - 6 y = 2 e^{t} - t^{2} - 2 t + 3

\int 20 - 0.1

\frac{d}{d y} (4 e^{2 y} (2 x^{2} + 4 x + 2 y + 1))

\int \frac{( ln ( x ^{3} ) )}{x} d x

What is (\partial)/(\partial x)(1+x^3+x^4) ?
The answer to (\partial)/(\partial x)(1+x^3+x^4) is 4x^3+3x^2