What is the derivative of (-x^2+9^2) ?

The derivative of (-x^2+9^2) is -4x(-x^2+9)

What is the first derivative of (-x^2+9^2) ?

The first derivative of (-x^2+9^2) is -4x(-x^2+9)

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\frac{d}{d x} ((- x^{2} + 9)^{2})

- 4 x (- x^{2} + 9)

Solution steps

\frac{d}{d x} ((- x^{2} + 9)^{2})

Apply the chain rule:

2 (- x^{2} + 9) \frac{d}{d x} (- x^{2} + 9)

= 2 (- x^{2} + 9) \frac{d}{d x} (- x^{2} + 9)

\frac{d}{d x} (- x^{2} + 9) = - 2 x

= 2 (- x^{2} + 9) (- 2 x)

Simplify

= - 4 x (- x^{2} + 9)

\frac{\partial}{\partial v} (x^{5} v^{2} + 2 y^{3} u - 3)

\int 2^{\frac{x}{2}} d x

x \cdot \frac{d y}{d x} = 2 x e^{x} - y + 6 x^{2}

\frac{d}{d y} (- x y sin (x) + 2 y cos (x))

y^{^{''}} + y = tan^{2} (x)

What is the derivative of (-x^2+9^2) ?
The derivative of (-x^2+9^2) is -4x(-x^2+9)
What is the first derivative of (-x^2+9^2) ?
The first derivative of (-x^2+9^2) is -4x(-x^2+9)