What is the d/(dy)(-xysin(x)+2ycos(x)) ?

The d/(dy)(-xysin(x)+2ycos(x)) is -xsin(x)+2cos(x)

What is the first d/(dy)(-xysin(x)+2ycos(x)) ?

The first d/(dy)(-xysin(x)+2ycos(x)) is -xsin(x)+2cos(x)

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\frac{d}{d y} (- x y sin (x) + 2 y cos (x))

- x sin (x) + 2 cos (x)

Solution steps

\frac{d}{d y} (- x y sin (x) + 2 y cos (x))

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d y} (x y sin (x)) + \frac{d}{d y} (2 y cos (x))

\frac{d}{d y} (x y sin (x)) = x sin (x)

\frac{d}{d y} (2 y cos (x)) = 2 cos (x)

= - x sin (x) + 2 cos (x)

y^{^{''}} + y = tan^{2} (x)

x^{2} y^{^{''}} - 2 x y^{^{'}} + 2 y = x^{2}

f (x) = \frac{x ^{2} + 5 x + 6}{x ^{2} - 4}

\int \frac{x}{x ^{4} - 1} d x

\frac{d}{d x} (- 2 e^{- x} cos (x))

What is the d/(dy)(-xysin(x)+2ycos(x)) ?
The d/(dy)(-xysin(x)+2ycos(x)) is -xsin(x)+2cos(x)
What is the first d/(dy)(-xysin(x)+2ycos(x)) ?
The first d/(dy)(-xysin(x)+2ycos(x)) is -xsin(x)+2cos(x)