What is the derivative of-2e^{-x}cos(x) ?

The derivative of-2e^{-x}cos(x) is -2(-e^{-x}cos(x)-e^{-x}sin(x))

What is the first derivative of-2e^{-x}cos(x) ?

The first derivative of-2e^{-x}cos(x) is -2(-e^{-x}cos(x)-e^{-x}sin(x))

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\frac{d}{d x} (- 2 e^{- x} cos (x))

- 2 (- e^{- x} cos (x) - e^{- x} sin (x))

Solution steps

\frac{d}{d x} (- 2 e^{- x} cos (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 \frac{d}{d x} (e^{- x} cos (x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = e^{- x}, g = cos (x)

= - 2 (\frac{d}{d x} (e^{- x}) cos (x) + \frac{d}{d x} (cos (x)) e^{- x})

\frac{d}{d x} (e^{- x}) = - e^{- x}

\frac{d}{d x} (cos (x)) = - sin (x)

= - 2 ((- e^{- x}) cos (x) + (- sin (x)) e^{- x})

Simplify

= - 2 (- e^{- x} cos (x) - e^{- x} sin (x))

y^{^{'}} + 2 y = 0, y (0) = 1

4 y^{^{''}} + 4 y^{^{'}} + 17 = 0

\frac{d}{d x} (\frac{x + 7}{4 x ^{2} e ^{x}})

\int arcsin (\frac{4}{3} x + 5) d x

(x^{3} + 2)^{5}, at x = - 1

What is the derivative of-2e^{-x}cos(x) ?
The derivative of-2e^{-x}cos(x) is -2(-e^{-x}cos(x)-e^{-x}sin(x))
What is the first derivative of-2e^{-x}cos(x) ?
The first derivative of-2e^{-x}cos(x) is -2(-e^{-x}cos(x)-e^{-x}sin(x))