What is the integral of (x^{1.7}+9x^{3.5}) ?

The integral of (x^{1.7}+9x^{3.5}) is 0.37037…x^{2.7}+2x^{4.5}+C

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integral of (x^{1.7}+9x^{3.5})

\int (x^{1.7} + 9 x^{3.5}) d x

0.37037 \dots x^{2.7} + 2 x^{4.5} + C

Solution steps

\int x^{1.7} + 9 x^{3.5} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{1.7} d x + \int 9 x^{3.5} d x

\int x^{1.7} d x = 0.37037 \dots x^{2.7}

\int 9 x^{3.5} d x = 2 x^{4.5}

= 0.37037 \dots x^{2.7} + 2 x^{4.5}

Add a constant to the solution

= 0.37037 \dots x^{2.7} + 2 x^{4.5} + C

\frac{d}{d x} (4 + x^{2})

y = (1 + 5 x)^{9}, (0, 1)

y^{2} y^{^{'}} + 5 = x^{2}

\int \frac{7 x - 5}{x ^{2} + 16} d x

f (x) = 6 - x^{2}, at x = 7

What is the integral of (x^{1.7}+9x^{3.5}) ?
The integral of (x^{1.7}+9x^{3.5}) is 0.37037…x^{2.7}+2x^{4.5}+C