What is the d/(dt)(1+sqrt(t)) ?

The d/(dt)(1+sqrt(t)) is 1/(2sqrt(t))

What is the first d/(dt)(1+sqrt(t)) ?

The first d/(dt)(1+sqrt(t)) is 1/(2sqrt(t))

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\frac{d}{d t} (1 + t)

\frac{1}{2 t}

Solution steps

\frac{d}{d t} (1 + t)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (1) + \frac{d}{d t} (t)

\frac{d}{d t} (1) = 0

\frac{d}{d t} (t) = \frac{1}{2 t}

= 0 + \frac{1}{2 t}

Simplify

= \frac{1}{2 t}

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What is the d/(dt)(1+sqrt(t)) ?
The d/(dt)(1+sqrt(t)) is 1/(2sqrt(t))
What is the first d/(dt)(1+sqrt(t)) ?
The first d/(dt)(1+sqrt(t)) is 1/(2sqrt(t))