What is the derivative of x^4-2x^2-3 ?

The derivative of x^4-2x^2-3 is 4x^3-4x

What is the first derivative of x^4-2x^2-3 ?

The first derivative of x^4-2x^2-3 is 4x^3-4x

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\frac{d}{d x} (x^{4} - 2 x^{2} - 3)

4 x^{3} - 4 x

Solution steps

\frac{d}{d x} (x^{4} - 2 x^{2} - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) - \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (3)

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (3) = 0

= 4 x^{3} - 4 x - 0

Simplify

= 4 x^{3} - 4 x

\int \frac{x + 7}{x ^{2} + 25} d x

\int x cos (3 x^{2}) d x

x \to 0 lim (\frac{1 + x}{x})

y = (5 x^{2} + x) (x - x^{2})

y = - x^{2} + 2 x + 6, y = - x + 6

What is the derivative of x^4-2x^2-3 ?
The derivative of x^4-2x^2-3 is 4x^3-4x
What is the first derivative of x^4-2x^2-3 ?
The first derivative of x^4-2x^2-3 is 4x^3-4x