What is the limit as x approaches 0 of (1+x)/x ?

The limit as x approaches 0 of (1+x)/x is diverges

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limit as x approaches 0 of (1+x)/x

x \to 0 lim (\frac{1 + x}{x})

diverges

Solution steps

x \to 0 lim (\frac{1 + x}{x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{1 + x}{x}) = \infty

x \to 0 - lim (\frac{1 + x}{x}) = - \infty

= diverges

y = (5 x^{2} + x) (x - x^{2})

y = - x^{2} + 2 x + 6, y = - x + 6

\int x^{2} + sin (x) + 1 d x

x \to - \infty lim (\frac{8 x ^{3}}{9 x ^{4}})

\int - cos (x) 2 x d x

What is the limit as x approaches 0 of (1+x)/x ?
The limit as x approaches 0 of (1+x)/x is diverges