What is the limit as x approaches 0+of xlog_{e}(x) ?

The limit as x approaches 0+of xlog_{e}(x) is 0

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limit as x approaches 0+of xlog_{e}(x)

x \to 0 + lim (x lo g_{e} (x))

0

Solution steps

x \to 0 + lim (x lo g_{e} (x))

Simplify

lo g_{e} (x) : ln (x)

= x \to 0 + lim (x ln (x))

Rewrite for L'Hopital

= x \to 0 + lim (\frac{ln ( x )}{\frac{1}{x}})

Apply L'Hopital's Rule

: x \to 0 + lim (\frac{\frac{1}{x}}{- \frac{1}{x ^{2}}})

= x \to 0 + lim (\frac{\frac{1}{x}}{- \frac{1}{x ^{2}}})

Simplify

\frac{\frac{1}{x}}{- \frac{1}{x ^{2}}} : - x

= x \to 0 + lim (- x)

Plug in the value

x = 0

= - 0

Simplify

= 0

- 8 (64 e^{- 4 x^{2}} x^{3} - 24 e^{- 4 x^{2}} x)

\frac{t ^{2}}{2}

\int e^{- s t} (2 t + 1) d t

y = \frac{1}{x ^{2}}, y = x, y = \frac{1}{8} x

\frac{d}{d x} (50 e^{- 0.5 x} - (\frac{5}{x}))

What is the limit as x approaches 0+of xlog_{e}(x) ?
The limit as x approaches 0+of xlog_{e}(x) is 0