What is the tangent of y^2=5x^4-x^2,(1,2) ?

The tangent of y^2=5x^4-x^2,(1,2) is y= 9/2 x-5/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of y^2=5x^4-x^2,(1,2)

tangent of

y^{2} = 5 x^{4} - x^{2}, (1, 2)

y = \frac{9}{2} x - \frac{5}{2}

Solution steps

Find the slope of

y^{2} = 5 x^{4} - x^{2} : \frac{d y}{d x} = \frac{x ( 10 x ^{2} - 1 )}{y}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{9}{2}

Find the line with slope m=

\frac{9}{2}

and passing through

(1, 2) : y = \frac{9}{2} x - \frac{5}{2}

y = \frac{9}{2} x - \frac{5}{2}

x \to 0 lim (\frac{e ^{x} - 1}{12 x})

\int \frac{5 sin ( x ) + 2 sec ( x )}{tan ( x )} d x

e^{3 t} sin (2 t)

\int_{0}^{0.6} 600 x d x

\int \frac{1}{500} e^{- \frac{1}{500} t} d t

What is the tangent of y^2=5x^4-x^2,(1,2) ?
The tangent of y^2=5x^4-x^2,(1,2) is y= 9/2 x-5/2