en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area y=x^2,y=sqrt(x)

Solution

area

y = x^{2}, y = x

Solution

\frac{1}{3}

+1

Decimal Notation

0.33333 \dots

Solution steps

Apply the area formula:

\int_{0}^{1} x^{2} - x d x

Solve

\int_{0}^{1} x^{2} - x d x : \frac{1}{3}

The area is:

= \frac{1}{3}

Popular Examples

(\partial)/(\partial y)(sin(x^2))

\frac{\partial}{\partial y} (sin (x^{2}))

slope ofintercept (0,-14),(-7,0)slope intercept

(0, - 14), (- 7, 0)

integral of (ln(x))x^2

\int (ln (x)) x^{2} d x

limit as x approaches 1/2 of x^3-x^2-x+1

x \to \frac{1}{2} lim (x^{3} - x^{2} - x + 1)

integral from 0 to 3 of x^2-4

\int_{0}^{3} x^{2} - 4 d x

Frequently Asked Questions (FAQ)

What is area y=x^2,y=sqrt(x) ?
The answer to area y=x^2,y=sqrt(x) is 1/3