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Popular >

integral from 0 to 3 of x^2-4

Solution

\int_{0}^{3} x^{2} - 4 d x

Solution

- 3

Solution steps

\int_{0}^{3} x^{2} - 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{3} x^{2} d x - \int_{0}^{3} 4 d x

\int_{0}^{3} x^{2} d x = 9

\int_{0}^{3} 4 d x = 12

= 9 - 12

Simplify

= - 3

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(dy)/(dx)+1/x y=x^2y^3

\frac{d y}{d x} + \frac{1}{x} y = x^{2} y^{3}

(\partial)/(\partial x)(1/(4-3x))

\frac{\partial}{\partial x} (\frac{1}{4 - 3 x})

Frequently Asked Questions (FAQ)

What is the integral from 0 to 3 of x^2-4 ?
The integral from 0 to 3 of x^2-4 is -3