What is the solution for (dy)/(dx)+1/x y=x^2y^3 ?

The solution for (dy)/(dx)+1/x y=x^2y^3 is y= 1/(xsqrt(-2x+c_{1))},y=-1/(xsqrt(-2x+c_{1))}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)+1/x y=x^2y^3

\frac{d y}{d x} + \frac{1}{x} y = x^{2} y^{3}

y = \frac{1}{x - 2 x + c _{1}}, y = - \frac{1}{x - 2 x + c _{1}}

Solution steps

\frac{d y}{d x} + \frac{1}{x} y = x^{2} y^{3}

Solve Bernoulli ODE:

y = \frac{1}{x - 2 x + c _{1}}, y = - \frac{1}{x - 2 x + c _{1}}

y = \frac{1}{x - 2 x + c _{1}}, y = - \frac{1}{x - 2 x + c _{1}}

\frac{\partial}{\partial x} (\frac{1}{4 - 3 x})

x \to 0 lim (\frac{( 3 ^{x} - 5 ^{x} )}{x})

\frac{d}{d x} ((ln (2 x))^{4})

\int_{4}^{9} 6 x d x

x^{5} + x^{2} y^{3} = 0

What is the solution for (dy)/(dx)+1/x y=x^2y^3 ?
The solution for (dy)/(dx)+1/x y=x^2y^3 is y= 1/(xsqrt(-2x+c_{1))},y=-1/(xsqrt(-2x+c_{1))}