What is the integral from 2 to 3 of x/(sqrt(x^2-1)) ?

The integral from 2 to 3 of x/(sqrt(x^2-1)) is 2sqrt(2)-sqrt(3)

Popular >

integral from 2 to 3 of x/(sqrt(x^2-1))

\int_{2}^{3} \frac{x}{x ^{2} - 1} d x

22 - 3

Decimal Notation

1.09637 \dots

Solution steps

\int_{2}^{3} \frac{x}{x ^{2} - 1} d x

Apply u-substitution

: \int_{3}^{8} \frac{1}{2 u} d u

= \int_{3}^{8} \frac{1}{2 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int_{3}^{8} \frac{1}{u} d u

Apply the Power Rule

: [2 u^{\frac{1}{2}}]_{3}^{8}

= \frac{1}{2} [2 u^{\frac{1}{2}}]_{3}^{8}

Apply radical rule:

= \frac{1}{2} [2 u]_{3}^{8}

Compute the boundaries:

42 - 23

= \frac{1}{2} (42 - 23)

Simplify

= 22 - 3

\frac{\partial}{\partial x} (\frac{2 x}{x ^{2} + y ^{4}})

\int \frac{e ^{6 x}}{e ^{12 x} + 49} d x

\frac{\partial}{\partial x} (sin (z))

cos (3 x)

y = \frac{7 x - 1}{8 x + 3}

What is the integral from 2 to 3 of x/(sqrt(x^2-1)) ?
The integral from 2 to 3 of x/(sqrt(x^2-1)) is 2sqrt(2)-sqrt(3)