What is the limit as x approaches 0 of ln(1+1/x) ?

The limit as x approaches 0 of ln(1+1/x) is Does not exist

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limit as x approaches 0 of ln(1+1/x)

x \to 0 lim (ln (1 + \frac{1}{x}))

Does not exist

Solution steps

x \to 0 lim (ln (1 + \frac{1}{x}))

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (ln (1 + \frac{1}{x})) = \infty

x \to 0 - lim (ln (1 + \frac{1}{x})) =

Does not exist

= Does not exist

\int e^{- 7 t} d t

16 y^{^{''}} + 2 y = 0

f (x) = - 9 x^{2}

\frac{d}{d x} (x^{2} - 2 x^{3})

\frac{d}{d x} (\frac{x ^{5}}{6})

What is the limit as x approaches 0 of ln(1+1/x) ?
The limit as x approaches 0 of ln(1+1/x) is Does not exist