What is the derivative of x^2-2x^3 ?

The derivative of x^2-2x^3 is 2x-6x^2

What is the first derivative of x^2-2x^3 ?

The first derivative of x^2-2x^3 is 2x-6x^2

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\frac{d}{d x} (x^{2} - 2 x^{3})

2 x - 6 x^{2}

Solution steps

\frac{d}{d x} (x^{2} - 2 x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (2 x^{3})

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

= 2 x - 6 x^{2}

\frac{d}{d x} (\frac{x ^{5}}{6})

sin (\frac{π x}{6})

\frac{d y}{d x} = 3

f (x) = \frac{- x ^{2} - 9}{( x ^{2} - 9 ) ^{2}}

2 x^{2}, at x = 1

What is the derivative of x^2-2x^3 ?
The derivative of x^2-2x^3 is 2x-6x^2
What is the first derivative of x^2-2x^3 ?
The first derivative of x^2-2x^3 is 2x-6x^2