What is the integral from 3 to infinity of e^{-2x} ?

The integral from 3 to infinity of e^{-2x} is 1/(2e^6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 3 to infinity of e^{-2x}

\int_{3}^{\infty} e^{- 2 x} d x

\frac{1}{2 e ^{6}}

Decimal Notation

0.00123 \dots

Solution steps

\int_{3}^{\infty} e^{- 2 x} d x

Compute the indefinite integral:

\int e^{- 2 x} d x = - \frac{1}{2} e^{- 2 x} + C

Compute the boundaries:

\int_{3}^{\infty} e^{- 2 x} d x = 0 - (- \frac{1}{2 e ^{6}})

= 0 - (- \frac{1}{2 e ^{6}})

Simplify

= \frac{1}{2 e ^{6}}

\int e^{- s x} \cdot x d x

f (x) = \frac{x ^{2} - 9}{x ^{2} + 3 x}

y = x, y = 2 x 100 - x^{2}

f (x) = 186.7

y^{^{''}} - y^{^{'}} + y = 3 sin (t) - 15 e^{2 t}

What is the integral from 3 to infinity of e^{-2x} ?
The integral from 3 to infinity of e^{-2x} is 1/(2e^6)