What is the derivative of Ce^{-2x} ?

The derivative of Ce^{-2x} is -2e^{-2x}C

What is the first derivative of Ce^{-2x} ?

The first derivative of Ce^{-2x} is -2e^{-2x}C

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\frac{d}{d x} (C e^{- 2 x})

- 2 e^{- 2 x} C

Solution steps

\frac{d}{d x} (C e^{- 2 x})

Treat

C

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= C \frac{d}{d x} (e^{- 2 x})

Apply the chain rule:

e^{- 2 x} \frac{d}{d x} (- 2 x)

= e^{- 2 x} \frac{d}{d x} (- 2 x)

\frac{d}{d x} (- 2 x) = - 2

= C e^{- 2 x} (- 2)

Simplify

= - 2 e^{- 2 x} C

\int 3^{s i n (x)} cos (x) d x

P^{^{'}} = k P

9 t

\frac{d}{d x} (16 x^{\frac{3}{2}})

\frac{d}{d x} (2 x^{\frac{3}{4}} + 4 x^{- \frac{1}{4}})

What is the derivative of Ce^{-2x} ?
The derivative of Ce^{-2x} is -2e^{-2x}C
What is the first derivative of Ce^{-2x} ?
The first derivative of Ce^{-2x} is -2e^{-2x}C