What is the derivative of sqrt(18+x) ?

The derivative of sqrt(18+x) is 1/(2sqrt(18+x))

What is the first derivative of sqrt(18+x) ?

The first derivative of sqrt(18+x) is 1/(2sqrt(18+x))

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\frac{d}{d x} (18 + x)

\frac{1}{2 18 + x}

Solution steps

\frac{d}{d x} (18 + x)

Apply the chain rule:

\frac{1}{2 18 + x} \frac{d}{d x} (18 + x)

= \frac{1}{2 18 + x} \frac{d}{d x} (18 + x)

\frac{d}{d x} (18 + x) = 1

= \frac{1}{2 18 + x} \cdot 1

Simplify

= \frac{1}{2 18 + x}

\int \frac{3 x + 1}{x ^{2} + 3 x - 10} d x

\frac{8 e ^{2 w} + 3 e ^{w}}{e ^{w}}

\int \frac{3 x ^{2} + 5 x - 4}{( x ^{2} - 1 ) ( x + 1 )} d x

\frac{\partial}{\partial x} (- 4 sin (x))

What is the derivative of sqrt(18+x) ?
The derivative of sqrt(18+x) is 1/(2sqrt(18+x))
What is the first derivative of sqrt(18+x) ?
The first derivative of sqrt(18+x) is 1/(2sqrt(18+x))