What is the derivative of (2x^2-3^2) ?

The derivative of (2x^2-3^2) is 8x(2x^2-3)

What is the first derivative of (2x^2-3^2) ?

The first derivative of (2x^2-3^2) is 8x(2x^2-3)

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\frac{d}{d x} ((2 x^{2} - 3)^{2})

8 x (2 x^{2} - 3)

Solution steps

\frac{d}{d x} ((2 x^{2} - 3)^{2})

Apply the chain rule:

2 (2 x^{2} - 3) \frac{d}{d x} (2 x^{2} - 3)

= 2 (2 x^{2} - 3) \frac{d}{d x} (2 x^{2} - 3)

\frac{d}{d x} (2 x^{2} - 3) = 4 x

= 2 (2 x^{2} - 3) \cdot 4 x

Simplify

= 8 x (2 x^{2} - 3)

x \to 3 lim (4 x + ∣ x - 3 ∣)

\frac{1}{4 - x}

\int θ cos^{2} (θ) d θ

y = (\frac{x}{7} + 9)^{\frac{3}{2}}

\frac{d}{d x} (\frac{x - 1}{x ^{2} + x - 2})

What is the derivative of (2x^2-3^2) ?
The derivative of (2x^2-3^2) is 8x(2x^2-3)
What is the first derivative of (2x^2-3^2) ?
The first derivative of (2x^2-3^2) is 8x(2x^2-3)