What is the derivative of x^{1/3}-1 ?

The derivative of x^{1/3}-1 is 1/(3x^{2/3)}

What is the first derivative of x^{1/3}-1 ?

The first derivative of x^{1/3}-1 is 1/(3x^{2/3)}

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derivative of

x^{\frac{1}{3}} - 1

\frac{1}{3 x ^{\frac{2}{3}}}

Solution steps

\frac{d}{d x} (x^{\frac{1}{3}} - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{\frac{1}{3}}) - \frac{d}{d x} (1)

\frac{d}{d x} (x^{\frac{1}{3}}) = \frac{1}{3 x ^{\frac{2}{3}}}

\frac{d}{d x} (1) = 0

= \frac{1}{3 x ^{\frac{2}{3}}} - 0

Simplify

= \frac{1}{3 x ^{\frac{2}{3}}}

\frac{d}{d t} (\frac{1}{( t + 1 ) ^{2}})

\int 3 x y^{2} d y

\frac{\partial}{\partial x} (e^{e^{y} (1 + e^{x}) - 2})

x^{2} - 2, - (x - 1)^{2} + 3

\int x^{4} (3 x^{5} - 1)^{6} d x

What is the derivative of x^{1/3}-1 ?
The derivative of x^{1/3}-1 is 1/(3x^{2/3)}
What is the first derivative of x^{1/3}-1 ?
The first derivative of x^{1/3}-1 is 1/(3x^{2/3)}