What is the derivative of y=(4x^2+5)(3x-5) ?

The derivative of y=(4x^2+5)(3x-5) is 36x^2-40x+15

What is the first derivative of y=(4x^2+5)(3x-5) ?

The first derivative of y=(4x^2+5)(3x-5) is 36x^2-40x+15

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derivative of

y = (4 x^{2} + 5) (3 x - 5)

36 x^{2} - 40 x + 15

Solution steps

\frac{d}{d x} ((4 x^{2} + 5) (3 x - 5))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 4 x^{2} + 5, g = 3 x - 5

= \frac{d}{d x} (4 x^{2} + 5) (3 x - 5) + \frac{d}{d x} (3 x - 5) (4 x^{2} + 5)

\frac{d}{d x} (4 x^{2} + 5) = 8 x

\frac{d}{d x} (3 x - 5) = 3

= 8 x (3 x - 5) + 3 (4 x^{2} + 5)

Simplify

8 x (3 x - 5) + 3 (4 x^{2} + 5) : 36 x^{2} - 40 x + 15

= 36 x^{2} - 40 x + 15

2 x^{3} - 3 x^{2} - 72 x + 2

\frac{s + 1}{s ^{2} - 4 s}

2 \cdot e^{x^{2} - 4 x}

\int 2 x - 5 d x

\int 8 x ln (3 x) d x

What is the derivative of y=(4x^2+5)(3x-5) ?
The derivative of y=(4x^2+5)(3x-5) is 36x^2-40x+15
What is the first derivative of y=(4x^2+5)(3x-5) ?
The first derivative of y=(4x^2+5)(3x-5) is 36x^2-40x+15