What is the integral from-infinity to 1 of 3^x ?

The integral from-infinity to 1 of 3^x is 3/(ln(3))

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integral from-infinity to 1 of 3^x

\int_{- \infty}^{1} 3^{x} d x

\frac{3}{ln ( 3 )}

Decimal

2.73071 \dots

Solution steps

\int_{- \infty}^{1} 3^{x} d x

Compute the indefinite integral:

\int 3^{x} d x = \frac{3 ^{x}}{ln ( 3 )} + C

Compute the boundaries:

\int_{- \infty}^{1} 3^{x} d x = \frac{3}{ln ( 3 )} - 0

= \frac{3}{ln ( 3 )} - 0

Simplify

= \frac{3}{ln ( 3 )}

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8 x + 7 cos (x)

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What is the integral from-infinity to 1 of 3^x ?
The integral from-infinity to 1 of 3^x is 3/(ln(3))