What is the derivative of 4/t ?

The derivative of 4/t is -4/(t^2)

What is the first derivative of 4/t ?

The first derivative of 4/t is -4/(t^2)

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derivative of

\frac{4}{t}

- \frac{4}{t ^{2}}

Solution steps

\frac{d}{d t} (\frac{4}{t})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d t} (\frac{1}{t})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 4 \frac{d}{d t} (t^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 4 (- 1 \cdot t^{- 1 - 1})

Simplify

4 (- 1 \cdot t^{- 1 - 1}) : - \frac{4}{t ^{2}}

= - \frac{4}{t ^{2}}

\int_{0}^{6} \frac{1}{x - 3} d x

\frac{x ^{2}}{3 x + 1}

\int cos (\frac{nπ x}{2 π}) d x

x \to 2 - lim (\frac{3}{2 - x})

f^{^{'}} (x) = 2 x^{2} + x - 1