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Popular >

area y=x+1,y=x^2-1

Solution

area

y = x + 1, y = x^{2} - 1

Solution

\frac{9}{2}

+1

Decimal Notation

4.5

Solution steps

Apply the area formula:

\int_{- 1}^{2} x + 1 - (x^{2} - 1) d x

Solve

\int_{- 1}^{2} x + 1 - (x^{2} - 1) d x : \frac{9}{2}

The area is:

= \frac{9}{2}

Popular Examples

integral of (x^2-x+30)/(x^3+5x)

\int \frac{x ^{2} - x + 30}{x ^{3} + 5 x} d x

(\partial)/(\partial x)(cos(w+x)sin(y-z))

\frac{\partial}{\partial x} (cos (w + x) sin (y - z))

\frac{d}{d t} (3 t - 2)

integral from 0 to 1 of 1/((x+1)(x+2))

\int_{0}^{1} \frac{1}{( x + 1 ) ( x + 2 )} d x

tangent of f(x)=17tan(x),\at x= pi/4 tangent of

f (x) = 17 tan (x), at x = \frac{π}{4}

Frequently Asked Questions (FAQ)

What is area y=x+1,y=x^2-1 ?
The answer to area y=x+1,y=x^2-1 is 9/2