What is area y=0,y=sqrt(x),y=x-2 ?

The answer to area y=0,y=sqrt(x),y=x-2 is 10/3

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area y=0,y=sqrt(x),y=x-2

area

y = 0, y = x, y = x - 2

\frac{10}{3}

Decimal Notation

3.33333 \dots

Solution steps

To find the intersection points solve

f_{i} (x) = f_{j} (x)

0 = x : x = 0

0 = x - 2 : x = 2

x = x - 2 : x = 4

= \int_{0}^{2} ∣ f_{1} (x) - f_{2} (x) ∣ d x + \int_{2}^{4} ∣ f_{2} (x) - f_{3} (x) ∣ d x

= \int_{0}^{2} 0 - x d x + \int_{2}^{4} x - (x - 2) d x

\int_{0}^{2} 0 - x d x = \frac{4 2}{3}

\int_{2}^{4} x - (x - 2) d x = \frac{16 - 4 2}{3} - 2

= \frac{4 2}{3} + \frac{16 - 4 2}{3} - 2

Simplify

= \frac{10}{3}

\frac{\partial}{\partial x} ((3 x - 1)^{2} (x^{3} + 1)^{2})

y = (x + 3)^{3}

\frac{d y}{d t} = - \frac{y}{t}

\int \frac{6}{x ^{2} - 1} d x

f (x) = 4 x^{2} sin (x) - 7 x

What is area y=0,y=sqrt(x),y=x-2 ?
The answer to area y=0,y=sqrt(x),y=x-2 is 10/3