What is (\partial)/(\partial x)(xyz-e^z) ?

The answer to (\partial)/(\partial x)(xyz-e^z) is yz

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(\partial)/(\partial x)(xyz-e^z)

\frac{\partial}{\partial x} (x yz - e^{z})

yz

Solution steps

\frac{\partial}{\partial x} (x yz - e^{z})

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x yz) - \frac{\partial}{\partial x} (e^{z})

\frac{\partial}{\partial x} (x yz) = yz

\frac{\partial}{\partial x} (e^{z}) = 0

= yz - 0

Simplify

= yz

(x^{2} - y x^{2}) d y + y^{2} (1 + x) d x = 0

\frac{\partial}{\partial t} (x + y sin (t))

\int t^{2} - 9 d t

\int (3 x^{2} + 4 x + 2) d x

\frac{d}{d x} (\frac{48}{( 1 - 2 x ) ^{4}})

What is (\partial)/(\partial x)(xyz-e^z) ?
The answer to (\partial)/(\partial x)(xyz-e^z) is yz