What is the tangent of f(x)=3x-4x^2,(-1,-7) ?

The tangent of f(x)=3x-4x^2,(-1,-7) is y=11x+4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=3x-4x^2,(-1,-7)

tangent of

f (x) = 3 x - 4 x^{2}, (- 1, - 7)

y = 11 x + 4

Solution steps

Find the slope of

f (x) = 3 x - 4 x^{2} : \frac{df ( x )}{d x} = 3 - 8 x

Compute the slope of

f (x) = 3 x - 4 x^{2}

(- 1, - 7) : m = 11

Find the line with slope m=

11

and passing through

(- 1, - 7) : y = 11 x + 4

y = 11 x + 4

\int 5 x x + 4 d x

\frac{d}{d x} ((1 - x)^{\frac{2}{3}})

n = 0 \sum \infty \frac{1}{3 ^{n} + 2}

\int θ cos (θ) d θ

\int \frac{x ^{4}}{1 - x ^{2}} d x

What is the tangent of f(x)=3x-4x^2,(-1,-7) ?
The tangent of f(x)=3x-4x^2,(-1,-7) is y=11x+4