What is the solution for y^{''}+ay-b=0 ?

The solution for y^{''}+ay-b=0 is y=c_{1}cos(sqrt(a)t)+c_{2}sin(sqrt(a)t)+b/a

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y^{''}+ay-b=0

y^{^{''}} + a y - b = 0

y = c_{1} cos (a t) + c_{2} sin (a t) + \frac{b}{a}

Solution steps

y^{''} (t) + a y (t) - b = 0

Solve linear ODE:

y = c_{1} cos (a t) + c_{2} sin (a t) + \frac{b}{a}

y = c_{1} cos (a t) + c_{2} sin (a t) + \frac{b}{a}

2 x^{5} + 3 y y^{^{'}} = 0

\int_{- 1}^{3} (- x^{2} + 2 x + 3) d x

\int \frac{1}{e ^{x}} d x

\int_{0}^{2} (8 t i - t^{3} j + 4 t^{7} k) d t

x \to 3 - lim (6 - x)

What is the solution for y^{''}+ay-b=0 ?
The solution for y^{''}+ay-b=0 is y=c_{1}cos(sqrt(a)t)+c_{2}sin(sqrt(a)t)+b/a