What is the derivative of 6xy+5x^2 ?

The derivative of 6xy+5x^2 is 6(y+x(dy)/(dx))+10x

What is the first derivative of 6xy+5x^2 ?

The first derivative of 6xy+5x^2 is 6(y+x(dy)/(dx))+10x

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\frac{d}{d x} (6 x y + 5 x^{2})

6 (y + x \frac{d y}{d x}) + 10 x

Solution steps

\frac{d}{d x} (6 x y + 5 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (6 x y) + \frac{d}{d x} (5 x^{2})

\frac{d}{d x} (6 x y) = 6 (y + x \frac{d y}{d x})

\frac{d}{d x} (5 x^{2}) = 10 x

= 6 (y + x \frac{d y}{d x}) + 10 x

\int \frac{1}{( x - 43 ) ^{0.92}} d x

co tan (x)

f (x) = e^{2 x} + 2 e^{2 x} x

\int (8 x + 7) d x

f (x) = \frac{1 - x}{1 + x}

What is the derivative of 6xy+5x^2 ?
The derivative of 6xy+5x^2 is 6(y+x(dy)/(dx))+10x
What is the first derivative of 6xy+5x^2 ?
The first derivative of 6xy+5x^2 is 6(y+x(dy)/(dx))+10x