What is the derivative of e^{3x}+b ?

The derivative of e^{3x}+b is 3e^{3x}

What is the first derivative of e^{3x}+b ?

The first derivative of e^{3x}+b is 3e^{3x}

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\frac{d}{d x} (e^{3 x} + b)

3 e^{3 x}

Solution steps

\frac{d}{d x} (e^{3 x} + b)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{3 x}) + \frac{d b}{d x}

\frac{d}{d x} (e^{3 x}) = e^{3 x} \cdot 3

\frac{d b}{d x} = 0

= e^{3 x} \cdot 3 + 0

Simplify

= 3 e^{3 x}

\int x^{2} 3 x + 3 d x

\frac{d}{d x} (4 x^{2} - x)

\int 4 x (2 x^{2} + 1)^{8} d x

f (x) = x^{2} - 5, at x = 1

x^{3}, at \frac{16}{3}

What is the derivative of e^{3x}+b ?
The derivative of e^{3x}+b is 3e^{3x}
What is the first derivative of e^{3x}+b ?
The first derivative of e^{3x}+b is 3e^{3x}