en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area y=x^2-1,y=3

Solution

area

y = x^{2} - 1, y = 3

Solution

\frac{32}{3}

+1

Decimal

10.66666 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{2} x^{2} - 4 d x

Solve

\int_{- 2}^{2} x^{2} - 4 d x : \frac{32}{3}

The area is:

= \frac{32}{3}

Graph

Popular Examples

(\partial)/(\partial x)(0.4x-4)

\frac{\partial}{\partial x} (0.4 x - 4)

(d^2y)/(dx^2)-4y=0

\frac{d ^{2} y}{d x ^{2}} - 4 y = 0

integral from 0 to N of e^{-st}*sin(5t)

\int_{0}^{N} e^{- s t} \cdot sin (5 t) d t

(\partial)/(\partial x)(xe^{2yz})

\frac{\partial}{\partial x} (x e^{2 yz})

(xdy)/(dx)=yln(xy)

\frac{x d y}{d x} = y ln (x y)

Frequently Asked Questions (FAQ)

What is area y=x^2-1,y=3 ?
The answer to area y=x^2-1,y=3 is 32/3