What is the solution for x^2y^'=xy+x^2e^{y/x} ?

The solution for x^2y^'=xy+x^2e^{y/x} is y=-xln(-ln(x)-c_{1})

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x^2y^'=xy+x^2e^{y/x}

x^{2} y^{^{'}} = x y + x^{2} e^{\frac{y}{x}}

y = - x ln (- ln (x) - c_{1})

Solution steps

x^{2} y^{'} (x) = x y + x^{2} e^{\frac{y}{x}}

Solve using substitution:

y = - x ln (- ln (x) - c_{1})

y = - x ln (- ln (x) - c_{1})

\frac{d}{d x} (3 x + 2 x ln (x))

\frac{\partial}{\partial y} (e^{- 2 x} cos (2 y))

\int (1 - x)^{4} d x

\frac{5 n ^{3} - 3 n + 1}{2 n - n ^{4}}

- x^{2} + 3 x + a

What is the solution for x^2y^'=xy+x^2e^{y/x} ?
The solution for x^2y^'=xy+x^2e^{y/x} is y=-xln(-ln(x)-c_{1})